php&mysql 在渲染另一个表的输出时搜索 mysql 表

Question

I have MYSQL table1 with columns (id(primary key), name, location, type) and table2 with columns (table1id(relation), confirmation(int(1 or 2))

now what I would like to do is the following . I want to get data from table1 and render it to HTML table (I can do that easly) my problem is the following . I want to give each HTML Table row a CSS class according to it's confirmation status from table2 .

I hope I could explain what i want in a correct way .

Answer 1

When you have two tables with related data, commonly you use a JOIN statement to get a result with the stuff from both tables. You can read about it here: JOIN Syntax . The MySQL docs can be hard to read at first, but if you're planning on using the database you should get started learning to read the docs as well.

In your case, it would be something like:

SELECT table1.*, table2.confirmation FROM table1 JOIN table2 ON table1.id = table2.table1id

There are different ways to join tables; this example will not return a result unless there is a row in table2 that matches the row in table1.

If you take a look at your result from that, you will see that your result has data from both tables.

When you render it, you just need to tweak your current code to add a class to each row. Inside the loop you use for rendering, just add a bit to each row:

$output .= '<tr class="' . ($resultRow->confirmation == 1 ? 'confirmed' : 'unconfirmed') . '">';
$output .= [whatever you currently render into the row];
$output .= '</tr>';

Obviously since you didn't post any code I can't really guess what your rendering loop looks like, but hopefully you can adapt what I wrote to match your style.