[英]Get string between two words using C# regex
I want to get text between two strings. 我想在两个字符串之间获取文本。 For this, I have tried the below code.
为此,我尝试了以下代码。
string q = "SELECT \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\".\"CUSTOMER_ID\" FROM \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\"";
Regex regex = new Regex("SELECT(.*)FROM");
var result = regex.Match(q).Value;
Output : SELECT \\"NORTHWIND\\".\\"CUSTOMER_DETAILS_NORTHWIND\\".\\"CUSTOMER_ID\\" FROM 输出 :SELECT \\“ NORTHWIND \\”。\\“ CUSTOMER_DETAILS_NORTHWIND \\”。\\“ CUSTOMER_ID \\” FROM
But I expected result without SELECT and FROM keyword. 但是我期望没有SELECT和FROM关键字的结果。
Expected Output: \\"NORTHWIND\\".\\"CUSTOMER_DETAILS_NORTHWIND\\".\\"CUSTOMER_ID\\" 预期输出: \\“ NORTHWIND \\”。\\“ CUSTOMER_DETAILS_NORTHWIND \\”。\\“ CUSTOMER_ID \\”
Can anyone suggest me how to achieve this? 谁能建议我如何实现这一目标?
string input = "SELECT \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\".\"CUSTOMER_ID\" FROM \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\"";
Regex regex = new Regex("SELECT(.*)FROM");
var result = regex.Match(input);
var output = result.Groups[1].ToString();
var match = Regex.Match(s, @"(?i)SELECT\s+(.+?)\s+FROM");
if (match.Success) {
Console.WriteLine(match.Groups[1].Value);
}
You can do it without RegEx
too. 您也可以不使用
RegEx
。
public static string GetBetweenTwoWords(string firstWord,string secondWord,string str){
var firstWordIndex = str.IndexOf(firstWord) + firstWord.Length;
var secondWordIndex = str.IndexOf(secondWord);
return str.Substring(firstWordIndex,secondWordIndex - firstWordIndex);
}
Test: 测试:
static void Main(string[] args)
{
string q = "SELECT \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\".\"CUSTOMER_ID\" FROM \"NORTHWIND\".\"CUSTOMER_DETAILS_NORTHWIND\"";
Console.WriteLine(GetBetweenTwoWords("SELECT","FROM",q));
}
Output: 输出:
"NORTHWIND"."CUSTOMER_DETAILS_NORTHWIND"."CUSTOMER_ID"
Here you go: 干得好:
"SELECT\s+\K\\".*(?=\sFROM)
no need for capture groups, just take the regex match (you can also remove the "SELECT\\s+ (it's just an extra verification) 无需捕获组,只需进行正则表达式匹配即可(您也可以删除“ SELECT \\ s +”(这只是额外的验证)
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