JavaScript包含年份的字符串排序数组使用

Question

I'm trying to sort an array of seasons by season and year, while removing duplicate seasons. The sort is not enough I guess I need to go by a regex but could not accomplish it

 const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"] console.log(_.uniq(myStringArray).sort(function(a, b) { return b - a; })); 

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Answer 1

You can try like this:

 const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"] console.log(_.uniq(myStringArray).sort(function(a, b) { return b.split(' ')[1] - a.split(' ')[1] || a.localeCompare(b); })); 

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Answer 2

You can sort by the year, then take the index of an created array that sets the order of season. To make the array unique, simply use a new Set

 const myStringArray = [...new Set(["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"])]; const order = ['Winter', 'Summer', 'Fall', 'Spring']; myStringArray.sort((a, b) => { let s = b.split(/\\s/); let s1 = a.split(/\\s/); return Number(s1[1]) - Number(s[1]) || order.indexOf(s[0]) * -1; }); console.log(myStringArray); 

Answer 3

If you are sure you your strings will always be in the format <Season YY> and digits will only appear once, you can use a quick and simple regex to sort desc:

 const myStringArray = ["Winter 17", "Summer 13", "Winter 15", "Summer 12", "Winter 17", "Summer 12", "Summer 17"] console.log(_.uniq(myStringArray).sort(function(a, b) { return +b.match(/\\d+/)[0] - +a.match(/\\d+/)[0]; })); 

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