[英]Remove all Optional empty/null values from arraylist in java
I need to remove all empty/null values from List<Optional<String>>
. 我需要从List<Optional<String>>
删除所有空/空值。
Example: 例:
List<Optional<String>> list = new ArrayList<>();
list.add(Optional.empty());
list.add(Optional.of("Str1"));
list.add(Optional.of("Str2"));
list.add(Optional.of("Str3"));
list.add(Optional.of("Str4"));
list.add(Optional.of("Str5"));
list.add(Optional.empty());
list.add(Optional.ofNullable(null));
Currently, I'm using one of the below approaches: 目前,我正在使用以下方法之一:
Way 1: 方式1:
List<String> collect = list.stream()
.filter(Optional::isPresent)
.map(obj ->obj.get())
.collect(Collectors.toList());
Way 2: 方式2:
List<Optional<String>> emptlist = new ArrayList<>();
emptlist.add(Optional.empty());
list.removeAll(emptlist);
Is there any other better way? 还有其他更好的方法吗?
With Java9 , you can do this using the newly added Optional::stream
API : 使用Java9 ,您可以使用新添加的Optional::stream
API执行此操作:
List<String> collect = list.stream()
.flatMap(Optional::stream)
.collect(Collectors.toList());
This method can be used to transform a
Stream
of optional elements to aStream
of present value elements . 此方法可以用来变换Stream
的可选元素的一个Stream
现值的元素 。
Sticking with Java8 , the Way1 in the question is good enough IMHO - 坚持使用Java8 ,问题中的Way1已经足够恕我直言 -
List<String> collect = list.stream()
.filter(Optional::isPresent)
.map(Optional::get) // just a small update of using reference
.collect(Collectors.toList());
removeIf
是最简单的方法:
list.removeIf(x -> !x.isPresent());
For anyone who wants to have a little fun or understand working of Optionals and Streams better (Java 8): 对于任何想要获得一点乐趣或者更好地理解Optionals和Streams的工作的人(Java 8):
List<String> collect=list.stream().
map(z->z.map(Stream::of)).
flatMap(ox->ox.orElseGet(Stream::empty)).
collect(Collectors.toList());
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.