在 Amazon S3 中删除文件的最快方法

Question

With boto3, one can delete files in a bucket as below

for object in bucket.objects.all():
    if 'xyz' in object.key:
        object.delete()

This sends one REST API call per file. If you have a large number of files, this can take a long time.

Is there a faster way to do this?

Answer 1

The easiest way to delete files is by using Amazon S3 Lifecycle Rules . Simply specify the prefix and an age (eg 1 day after creation) and S3 will delete the files for you!

However, this is not necessarily the fastest way to delete them -- it might take 24 hours until the rule is executed.

If you really want to delete the objects yourself, use delete_objects() instead of delete_object() . It can accept up to 1000 keys per call, which will be faster than deleting each object individually.

Answer 2

There are many ways to accomplish what you are asking.

Use Python's list comprehension, to get the list of objects that meet your criteria:

myobjects = [{'Key':obj.key} for obj in bucket.objects.all() if 'xyz' in obj.key]

Once you store the objects to be deleted in myobjects , call bulk delete :

bucket.delete_objects(Delete={ 'Objects': myobjects})

delete_objects(**kwargs)

This operation enables you to delete multiple objects from a bucket using a single HTTP request. You may specify up to 1000 keys.

If there are more than 1000 keys, then it is a matter looping through the list, slice 1000 keys in each iteration and call delete_objects()

Answer 3

Boto provides support for MultiDelete. Here's an example of how you would use it:

import boto.s3
conn = boto.s3.connect_to_region('us-east-1')  # or whatever region you want
bucket = conn.get_bucket('mybucket')
keys_to_delete = ['mykey1', 'mykey2', 'mykey3', 'mykey4']
result = bucket.delete_keys(keys_to_delete)