如何从数据库表中获取行值以在JavaScript / jQuery中使用它？
[英]How to get a row value from database table to use it in JavaScript / jQuery?
问题描述
I want to retrieve a row value from database. 
我想从数据库中检索行值。 Since we need serverside to access database we have to use PHP to retrive the value but I am not sure how to use this php in a .js file. 由于我们需要服务器端访问数据库，因此我们必须使用PHP来获取值，但是我不确定如何在.js文件中使用此php。
This is what I am trying but it does not work. 这是我正在尝试的方法，但是不起作用。 The reason is simple.. we can not write PHP inside a javascript file. 原因很简单..我们无法在JavaScript文件中编写PHP。
file.js: file.js：
<?php
$con = mysqli_connect($server, $db_user, $db_pwd, $db_name);
$username = $_SESSION['username'];
$sql = "SELECT * FROM Holders WHERE username='$username'";
$data = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($data);
$address = $row['address'];
?>
$( document ).ready(function() {
var addressFrmPHP = "<?= $address; ?>";
var url = "https://api.examlesite.io/api?module=account&action=bal&add=000000000&address="+addressFrmPHP+"&tag=latest&apikey=APIKEY";
});
How can I assign the php $address variable to javascript addressFrmPHP variable? 如何将php $address变量分配给javascript addressFrmPHP变量？
3 个解决方案
解决方案1
3 已采纳 2018-01-04 07:45:35
You have to create two files as shown below 您必须创建两个文件，如下所示
getdata.php
<?php
$con = mysqli_connect($server, $db_user, $db_pwd, $db_name);
$username = $_SESSION['username'];
$sql = "SELECT * FROM Holders WHERE username='$username'";
$data = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($data);
$address = $row['address'];
echo $address;
?>
file.js
$( document ).ready(function() {
/* AJAX for get data from php page */
$.post('getdata.php', function(address) {
var addressFrmPHP = address;
});
var url = "https://api.examlesite.io/api?module=account&action=bal&add=000000000&address="+addressFrmPHP+"&tag=latest&apikey=APIKEY";
});
解决方案2
1 2018-01-04 07:12:14
you have to do like this 你必须这样做
test.php test.php
<?php
$con = mysqli_connect($server, $db_user, $db_pwd, $db_name);
$username = $_SESSION['username'];
$sql = "SELECT * FROM Holders WHERE username='$username'";
$data = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($data);
$address = $row['address'];
echo '<script> var address= '.$address.';</scrpit>';
?>
<script type='text/javascript' src='js/file.js'></script>
file.js file.js
$( document ).ready(function() {
var addressFrmPHP = address;
var url = "https://api.examlesite.io/api?module=account&action=bal&add=000000000&address="+addressFrmPHP+"&tag=latest&apikey=APIKEY";
});
解决方案3
1 2018-01-04 08:04:07
Create One file Getdata.php and write the below code: 创建一个文件Getdata.php并编写以下代码：
<?php
$con = mysqli_connect($server, $db_user, $db_pwd, $db_name);
$username = 'nirav4491';
$sql = "SELECT * FROM Holders WHERE username='$username'";
$data = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($data);
$address = $row['address'];
?>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script type="application/javascript">
$(document).ready(function() {
var addressFrmPHP = '<?php echo $address; ?>';
var url = "https://api.examlesite.io/api?module=account&action=bal&add=000000000&address="+addressFrmPHP+"&tag=latest&apikey=APIKEY";
alert(url);
});
</script>
</head>
</html>
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