Java如何从字节流中读取64位无符号长

Question

I'm trying to read an unsigned long from byte stream (that has been generated by a C program). Since the number might be too big for a Java long I imagined the best way to do this would be to read the 8 bytes into a BigInteger (as below) but this doesn't work.

Would appreciate any help with a good way to do this.

    ByteBuffer bb = ByteBuffer.wrap(new byte[8]).order(ByteOrder.nativeOrder());
    bb.putLong(12345678910L);

    byte[] bytes = new byte[8];
    for(int i=0; i<8; i++){
        bytes[i] = bb.get(i);
    }

    BigInteger bi = new BigInteger(bytes);// bi is not correct

Answer 1

Try taking out the order call:

    ByteBuffer bb = ByteBuffer.wrap(new byte[8]);
    bb.putLong(12345678910L);