我希望能够从列表python分组相同的文件序列

Question

Working on a python function which parses a file containing a list of strings. Basically a walked folder structure parsed to a txt file so I don't have to work on real raid while in prod. That is also a requirement. To work from a txt file containing list of paths.

lpaths  =[
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot012/render/SC11_1_Shot012.v01_1025.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot012/render/SC11_1_Shot012.v01_1042.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot012/render/SC11_1_Shot012.v01_1016.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot012/2d/app/Shot012_v1.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot012/2d/app/Shot012_v02.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/3d/app2/workspace.cfg',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/3d/app2/scenes/SC11_1_Shot004_v01.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/3d/app2/scenes/Shot004_camera_v01.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/render/SC11_1_Shot004.v01_1112.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/render/SC11_1_Shot004.v01_1034.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/render/SC11_1_Shot004.v02_1116.exr',
    '/projects/0100/dbu/shots/11_1/SC11_1_Shot004/render/SC11_1_Shot004.v02_1126.exr'
    ]

This is partial list of the cleaned list version ive already worked out and works fine.

The real problem, need to parse all frames from a folder to into a list so it can hold a proper listed sequence. There could be 1 frame or 1000, also there are multiple sequences in same folder as seen in the list.

My goal is to have a list for each sequence in a folder, so I can push them ahead to do more work down the road.

Code:

groups = [list(group) for key, group in itertools.groupby(sorted(lpaths), len)]

pp.pprint(groups)

Answer 1

Since you seem to have differing naming conventions you need to write a function that takes a single string and, possibly using regular expressions , returns an unambiguous key for you to sort on, lets say that you names are critically identified by the shot number which can be identified by r".*[Ss]hot_?(\\d+).*\\.ext" you could return an integer for the match base 10 so discarding any leading 0s.

Since you also may have a version number you could do a similar operation to get an unambiguous version number, (and possibly only process the latest version of a given shot).