C开关无法识别字符串

Question

I am trying to take a user input in the form of a string and then use that in a switch, but it always ends up using the default case and not the case for the string I inputted. For the purpose of testing I am inputting just the letter y into this:

  char thing[1];
  scanf("%s",thing);
  switch(thing){
    case 'y' :
      printf("yup\n");
      break;
    default :
      printf("nope\n");
  }

Answer 1

This char array has one element. Your code is crying for a char here. You will do fine with a char and then get input and check it. Also here in switch you have used an pointer value which didn't match with the char like y etc . Went to default.

char thing;
if(scanf("%c",&thing) != 1){
   // error
}
..

If you want to use strcmp beware that you need to have null terminated char array.

char thing[3];
if(scanf("%2s",thing)!= 1){
  // error
}

if(strcmp(thing,"y") == 0){
  printf("yup\n");
}
else{
  printf("nope\n");
}

Also you could have done this with your code - but that is not helpful given that you can't use it as null terminated char array or string which many of the standard string processing function demands.

char thing[1];
if(scanf("%c",&thing[0]) != 1){
   // error
}
switch(thing[0]){
  case 'y' :
    printf("yup\n");
    break;
  default :
    printf("nope\n");
}