[英]How to get a count of each record in mysql query
I have two mysql tables, users
and orders
to track orders placed by each user. 我有两个mysql表, users
和orders
以跟踪每个用户下的订单。
I want to get a list of each user, and the total number of orders. 我想获取每个用户的列表以及订单总数。
For an individual, I could use: 对于个人,我可以使用:
SELECT users.name, (select count(*) from orders where orders.users_id = 1) as total
from users
where users.id = 1
Is there an efficient way to do this for all users simultaneously? 是否有一种有效的方式可以同时为所有用户执行此操作?
You can do it with a correlated subquery. 您可以使用相关子查询来实现。
SELECT users.name, (select count(*) from orders where orders.users_id = users.id) as total
from users
But a better way is with a join. 但是更好的方法是加入。
SELECT users.name, IFNULL(COUNT(orders.id), 0) AS total
FROM users
LEFT JOIN orders ON orders.users_id = users.id
GROUP BY users.id
It may actually be better to join with a subquery that aggregates, rather than aggregating after joining: 实际上,最好使用聚合的子查询进行合并,而不是在合并后进行聚合:
SELECT u.name, IFNULL(o.total, 0) AS total
FROM users as u
LEFT JOIN (
SELECT users_id, COUNT(*) AS total
FROM orders
GROUP BY users_id) AS o ON u.id = o.users_id
The key is really a GROUP BY: 关键确实是GROUP BY:
SELECT u.id, u.name, COUNT(*)
FROM users u
INNER JOIN orders o ON u.id = o.users_id
GROUP BY u.id, u.name
You could do something like that too, in this case only will return when there are records on order : 您也可以执行类似的操作,在这种情况下,只有在订单上有记录时才会返回:
SELECT users.name, count(*)
from users
join orders On orders.users_id = users.id
group by users.name
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