[英]Alamofire get request url parameters
I need to create a url like "myserverbaseurl.com/category/{id}/subcategory 我需要创建一个网址,例如“ myserverbaseurl.com/category/{id}/subcategory
{id} in this url needs to be parametric and can change. 此网址中的{id}必须是参数化的,可以更改。 The rest of the url is constant.
其余的URL是恒定的。 Does Alamofire have an easy way for this or I need to do this with String?
Alamofire是否有简便的方法,还是我需要用String做到这一点?
Start setting your parameter in a constant and use a function to make your call, for example: 开始在常量中设置参数并使用函数进行调用,例如:
func myAPICall(id: String){
let url = "myserverbaseurl.com/category/" + id + "/subcategory"
Alamofire.request(url).responseJSON { (response) in
....
}
}
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