从表2获取信息以及从表1获取信息

Question

I'm not experienced with SQl (and also not THAT much with php)
I'm currently am getting my info from a table from my database and putting it on my Website. Now I'm trying to get info from another table trough data from my 1st table trough $sql = "SELECT * FROM patients";
Example: In my current syntax row 3 called "species_id" is a '1'. In another table the ID is 1 and species = "cat". I want cat in my row where I drop the info from the first table.
in theory I want something like

$sql = "SELECT * FROM patients SELECT species_description 
        FROM species 
        WHERE species_id=species_id;";

(wich obviously doesnt work but I wanted you to have a better idea) How do I correctly do this (the best way)?

Answer 1

assuming you have species_id in your patientes table and this is the relation value for the id in species you could buil a join

    $sql = "SELECT patients.* , species.species_description
            FROM patients
            INNER JOIN species on patients.species_id=species.id;";

Answer 2

thanks everyone for an answer, i fixed it using this code

$sql = "SELECT patients.* , species.species_description
    FROM patients
    INNER JOIN species on patients.species_id = species.species_id;";

thanks to the answer from @scaisEdge (thank you!) and w3schools page on how to use INNER JOIN (never knew about that before) thanks!