如何按日期列表过滤日期和小时的数据框？

Question

I have the following dataframe, with several days and a measure every 15minutes:

                 CONSUMPTION
2016-11-01 01:00:00  3539
2016-11-01 01:15:00  3560
2016-11-01 01:30:00  3505
....
2016-11-02 01:00:00  3400
2016-11-02 01:15:00  3447
....
2016-11-03 01:00:00  2400
2016-11-03 01:15:00  2447

Every works if ask for a simple day:

df['2016-11-01']

and I get all the measure for that day, 96 measures:

    CONSUMPTION
2016-11-01 01:00:00  3539
2016-11-01 01:15:00  3560
2016-11-01 01:30:00  3505
....

But my problem is that I want to get a list of dates, and this doesn't work:

df[['2016-11-01','2016-11-03']]

The most I have achieved is this (but this is not what I want, observed that 1 get a measure per day, instead my 96 expected measures):

qwe=['2016-11-01','2016-11-03']
df.ix[df.index.to_datetime().isin(qwe)]

            CONSUMPTION
2016-11-01  3539
2016-11-03  2400

Any idea would be appreciated.....

Answer 1

Floor the datetime to Day and then use isin and loc ie

li = ['2016-11-01','2016-11-02']
df.loc[(df.index.floor('D').isin(li)),:]

                    CONSUMPTION
Date                            
2016-11-01 01:00:00         3539
2016-11-01 01:15:00         3560
2016-11-01 01:30:00         3505
2016-11-02 01:00:00         3400
2016-11-02 01:15:00         3447

Answer 2

This works for hours :

hours = [0, 6, 12, 18]
df.loc[(df.index.hour.isin(hours)),:]