Javascript数组浏览和比较

Question

I need to browse and compare two array and get the following result : For example:

T = [5,10,15];
V = [15,50,30];

I need to return the following values:

V[0]-T[0] = 15-5 = 10
V[1]-T[0] = 50-5 = 45
V[2]-T[0] = 30-5 = 25

The MAX of the three value = 45

V[0]-T[1] = 15-10 = 5
V[1]-T[1] = 50-10 = 40
V[2]-T[1] = 30-10 = 20

The MAX of the three value = 40

V[0]-T[2] = 15-15 = 0
V[1]-T[2] = 50-15 = 35
V[2]-T[2] = 30-15 = 15

The MAX of the three value = 35

I tried to do it by myself using this code:

 var T = [5,10,15]; var V = [15,50,30]; var X; for (var i = 0; i < T.length; ++i){ for (var j = 0; j < V.length; ++j) { X = V[j]-T[i]; console.log(V[j]-T[i]); } if ((V[j]-T[i]) >= X) { X = V[j]-T[i]; console.log(V[j]-T[i]); } else { console.log(X); } console.log('\\n'); } 

But i get the following result:

10
45
25
25
5
40
20
20
0
35
15
15

Answer 1

You could map t and take the maximum value of the mapped values of the subtraction.

This proposal features Array#map with arrow functions and Math.max with spread syntax ... for an array for taking it as parameters.

 var t = [5, 10, 15], v = [15, 50, 30], max = t.map(tt => Math.max(...v.map(vv => vv - tt))); console.log(max); 

ES5

 var t = [5, 10, 15], v = [15, 50, 30], i, j, max, result = []; for (i = 0; i < t.length; i++) { max = v[0] - t[i]; // take the first value of v for (j = 1; j < v.length; j++) { // iterate from the second value of v max = Math.max(max, v[j] - t[i]); // get max value } result.push(max); // store max } console.log(result);