[英]How do I use shell variables of awk script in system command?
I am troubleing in coverting hex to decimal from txt file using awk. 我在使用awk从txt文件中将十六进制转换为十进制时遇到了麻烦。
I want to do like this 我想这样做
awk -F' ' '{ system("echo '$((16#"$1"))'") '} $file_name
but not work... then I try other code 但没有工作...然后我尝试其他代码
awk -F' ' -v var="\"echo \x27\$((16#" '{var=var$1"))\x27\"" system(var) }' $file_name
also not work. 也行不通。 but print var then enter image description here
但是打印var然后在这里输入图像描述
what should i do? 我该怎么办?
To use GNU awk to convert hex to decimal: 要使用GNU awk将十六进制转换为十进制:
$ echo '0xFFFFFFFE' | awk -n '{printf "%i\n",$1}'
4294967294
Or: 要么:
$ x='0xFFFFFFFE'
$ awk -n -v x="$x" 'BEGIN{printf "%i\n",x}'
4294967294
Or: 要么:
$ x='0xFFFFFFFE'; awk -v x="$x" 'BEGIN{print strtonum(x)}'
4294967294
To convert hex to decimal using bash: 要使用bash将十六进制转换为十进制:
$ echo $((0xFFFFFFFE))
4294967294
Limitations: 限制:
1. GNU awk is limited to 52-bit integers.
2. The above could be extended to perform two's-complement arithmetic but it hasn't.
To avoid both these limitations, see the python solution below: 要避免这些限制,请参阅下面的python解决方案:
Awk does not handle long integers. Awk不处理长整数。 For long integers, consider this python script:
对于长整数,请考虑以下python脚本:
$ cat n.py
#!/usr/bin/python3
import sys
def h(x):
x = int(x, 16)
return x if x < 2**63 else x - 2**64
for line in sys.stdin:
print(*[h(x) for x in line.split()])
Let's use this input file: 让我们使用这个输入文件:
$ cat file
FFFFFFFFFFFFFFFF EFEFEFEFEFEFEFEF
When we run our script, we find: 当我们运行脚本时,我们发现:
$ python3 n.py <file
-1 -1157442765409226769
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