如何通过php从mysql数据库中获取单个参数？

Question

i'm not pro in php. i have a simple table like this:

game_id      name      score

and i used this query to get the rank of a player in mysql:

SELECT FIND_IN_SET( score, ( SELECT GROUP_CONCAT( score ORDER BY score ASC ) FROM highscores ) ) AS 'rank' FROM highscores where game_id = $game_id

it works and shows the rank in mysql but i cant get the rank number as a parameter in my php code.

I have tried with the following methods:

mysql_fetch_assoc();
mysql_free_result();
mysql_fetch_row();

But I didn't succeed to display (get) the actual value.

Answer 1

As has been notes in the comments you shouldn't use the mysql_* functions. I tend to use mysqli.

You can create a connection

$con = mysqli_connect(serverip,"myname","mypassword","mydatabase");
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

And execute a query

$result = $con->query($myquery) or die($con->error.__LINE__);

Once you have successfully executed the query

you can get a row with

$row =  $result->fetch_assoc()

and get the individual fields with

$row['score']

Answer 2

include ('dbconnection.php');


$sql = "SELECT game_id, score, ... from YOURTABLE where game_id = '$game_id'";

now you have to query it like

$query = mssql_query($sql, $connection);

and now u can fetch it with :

 while($row = mssql_fetch_assoc($query))
{
 echo $row["game_id"];
 echo $row["score"];
}

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