如何按路径对linux find命令进行排序

Question

I am writing a small shell script. there i want to get all the paths of files recursively. for that i am using bellow code.

for entry in `find . -type f`; do
       echo $entry 
done

getting the files recursively is okay. but it does not sort by path.

ex : the folder has 1,2,3,rename.sh (The shell script) files and a folder called test. inside that test folder again there are 1,2, 3 files. when i execute this code the out put is like this

./rename.sh
./1.png
./test/1.png
./test/2.jpg
./test/3.jpg
./2.jpg
./3.jpg

why is it not sorted by path. How do i sort it by the path so the out put wold be

./rename.sh
./1.png
./2.jpg
./3.jpg
./test/1.png
./test/2.jpg
./test/3.jpg

Answer 1

If you want content sorted, do it yourself . For a list of files, doing that safely means NUL-delimiting the names (so a file with a newline in its name doesn't get read as the names of two separate files and thus split apart during the sort process), and using sort -z (a GNU extension).

while IFS= read -r -d '' entry; do
  printf 'Processing: %s\n' "$entry"
done < <(find . -type f -print0 | sort -z)

See Using Find for guidance on using find reliably, and BashFAQ #1 for a discussion of the while read construct used here.