JavaScript正则表达式用百分号替换所有数字

Question

I have to remove all numbers with percentage sign in string.

For instance,

str = "test 12% test" -> "test test"
str = "test 12 % test" -> "test test"
str = "test 12%   test" -> "test test"
str = "test 1.2% test" -> "test test"

For now I cannot figure out how to fix the last one - it is number with dot. My current regexp is like this:

name = name.replace(/\d+ ?% ?/g, "");

ADDITIONAL SCENARIOS

str = "test 1.2%,test" -> "test ,test" // space is optional after %
str = "test (1.2%) test" -> "test test" // space is optional after %
str = "test 1.2%" -> "test" or "test " // space could be left after test if easier

Answer 1

You can add an optional non capturing group (?:\\.\\d+)? which checks for a dot and one or more digits. At the end your could add * to match zero or more whitespaces.

Explanation

• Match optional parenthesis \\(?
• Match one or more digits \\d+
• Optional non capturing group to match a dot and one or more digits (?:\\.\\d+)?
• Match an optional space ?
• Match a percentage sign %
• Match an optional closing parenthises \\)
• Match zero or more whitespaces *

\\(?\\d+(?:\\.\\d+)? ?%\\)? *

 var strings = [ "test 12% test", "test 12 % test", "test 12% test", "test 1.2% test", "test 1.2%,test", "test (1.2%) test", "test 1.2%" ]; for (var i = 0; i < strings.length; i++) { console.log(strings[i] + "-> " + strings[i].replace(/\\(?\\d+(?:\\.\\d+)? ?%\\)? */g, "")); } 

Answer 2

You could use the [] square brackets to specify a group to match.

here we are using

• \\d : digit
• \\. : literal .
• \\s : whitespace

 const strings = [ "test 12% test", "test 12 % test", "test 12% test", "test 1.2% test", "test whitespace", "test 12 test", "test 1.2%,test", "test (1.2%) test", "test 1.2%", ] strings.forEach( string => console.log(string, string.replace(/\\s\\(?[\\d\\.\\s]+\\%\\)?\\s*/g, ' ').trim()) ) 

 <script src="https://codepen.io/synthet1c/pen/KyQQmL.js"></script> 

Answer 3

This will get your output

Find [^\\S\\r\\n]*(?:\\d+(?:\\.\\d*)?|\\.\\d+)\\s*%[^\\S\\r\\n]*
Replace

https://regex101.com/r/EcbAXV/1

Formatted

 [^\S\r\n]*                    # Trim horizontal whitespace
 (?:                           # Valid number formats to find
      \d+ 
      (?: \. \d* )?
   |  \. \d+ 
 )
 \s*                           # Optional whitespace
 %                             # Literal percent
 [^\S\r\n]*                    # Trim horizontal whitespace