我正在制作破砖游戏，想知道是否有办法将这些砖放在一个变量下

Question

These are the bricks I have made for my game. Stack Overflow is not letting me put all of my bricks so these are 1/3 of them. The total amount is 60 (3 rows of 20).

#Bricks    
pygame.draw.rect(screen, (blue), (0,65,40,20), 0)
pygame.draw.rect(screen, (blue), (40,65,40,20), 0)
pygame.draw.rect(screen, (blue), (80,65,40,20), 0)
pygame.draw.rect(screen, (blue), (120,65,40,20), 0)
pygame.draw.rect(screen, (blue), (160,65,40,20), 0)
pygame.draw.rect(screen, (blue), (200,65,40,20), 0)
pygame.draw.rect(screen, (blue), (240,65,40,20), 0)
pygame.draw.rect(screen, (blue), (280,65,40,20), 0)
pygame.draw.rect(screen, (blue), (320,65,40,20), 0)
pygame.draw.rect(screen, (blue), (360,65,40,20), 0)
pygame.draw.rect(screen, (blue), (400,65,40,20), 0)
pygame.draw.rect(screen, (blue), (440,65,40,20), 0)
pygame.draw.rect(screen, (blue), (480,65,40,20), 0)
pygame.draw.rect(screen, (blue), (520,65,40,20), 0)
pygame.draw.rect(screen, (blue), (560,65,40,20), 0)
pygame.draw.rect(screen, (blue), (600,65,40,20), 0)
pygame.draw.rect(screen, (blue), (640,65,40,20), 0)
pygame.draw.rect(screen, (blue), (680,65,40,20), 0)
pygame.draw.rect(screen, (blue), (720,65,40,20), 0)
pygame.draw.rect(screen, (blue), (760,65,40,20), 0)

Is it possible I can put these bricks under one variable and also shorten this code? You're help is much appreciated. Thank you.

Answer 1

Simply use nested for loops to create list with all bricks.

I will use pygame.Rect() to keep position and size because I will use it to check collision.

all_bricks = []

for y in range(65, 106, 20):
    for x in range(0, 761, 40):
        brick_rect = pygame.Rect(x, y, 40, 20)
        all_bricks.append(brick_rect)

and then you can draw them using one for loop

for brick_rect in all_bricks:    
    pygame.draw.rect(screen, blue, brick_rect, 0)

or check collisions

untouched_bricks = []

for brick_rect in all_bricks:    
    if not ball_rect.colliderect(brick_rect):
        untouched_bricks.append(brick_rect)
    #else:
    #    print("Brick touched")

# keep only untouched bricks
all_bricks = unbreaked_bricks

---

To keep position and different color for every brick separately you will need more complex structure:

• list - ie. [blue, pygame.Rect(x, y, 40, 20), ...]
• dictionary - ie. {"color": blue, "rect": pygame.Rect(x, y, 40, 20), "other": ...} )
• class