在python中对dict值排序而没有排序功能

Question

I want to sort values of dictionary in list without using sort function.I tried below but its not working

dict1={"one":1,"two":2,"three":3}
list1=[]
for i in range(len(dict1)):
    sml=[a for a in dict1.values() if a ==min(dict1.values())]
    key1=[k for k,v in dict1.items() if v ==min(dict1.values())]
    del dict[key1]
    list1.append(sml)

print(list1)

Answer 1

Your approach is almost there. Your only mistake is that the lines

sml=[a for a in dict1.values() if a ==min(dict1.values())]
key1=[k for k,v in dict1.items() if v ==min(dict1.values())]

actually make sml and key1 lists with the first one containing the smallest value as its only element and the second containing the key of the smallest value as its only element.
(The syntax x = [....] will make x a list, even if there is only one element).

So everything will be fixed by making those lines as:

sml=[a for a in dict1.values() if a ==min(dict1.values())][0]
key1=[k for k,v in dict1.items() if v ==min(dict1.values())][0]