需要Shell脚本来获取创建的文件名

Question

I am writing a script to get output if a specific file is created successfully or failed.

Example: In a path /x/y/z/ everyday a file with name abc.out_timestamp will be created.

The script that i am working needs check if the file is created today or not and show the output accordingly.

Path : /x/y/z have the below files
abc.out0114181500
abc.out0115181600
abd.out0116182100

script to be run:

#!/bin/bash
TODAY=$(date +%m%d%y)

cd /x/y/z

if [ -f abc.out_$TODAY ]
then
      echo "$file creation successful"
else
     echo "$file creation not successful"
fi

output received: file creation not successful (though a file is created today) expected output: file creation successful

How can i correct this, can anyone please let me know how i can the output as file creation successful.

Thanks

Answer 1

You're 98% of the way there

#!/bin/bash
TODAY=$(date +%m%d%y)

cd /x/y/z

if [ -f abc.out${TODAY}???? ]
then
     echo "$file creation successful"
else
     echo "$file creation not successful"
fi

The pattern abc.out${TODAY}???? matches the filename with today's date followed by 4 more characters (and without the underscore, which was spurious).

If you want more validation, use

if [ -f abc.out${TODAY}[0-2][0-9][0-5][0-9] ]

I hope the abd. was a typo and it's really abc. However, if it could be abc or abd you can handle that with

if [ -f ab[cd].out${TODAY}[0-2][0-9][0-5][0-9] ]