如何将char *字符串转换为指向指针数组的指针，并将指针值分配给每个索引？

Question

I have a char * that is a long string and I want to create a pointer to a pointer(or pointer array). The char ** is set with the correct memory allocated and I'm trying to parse each word from the from the original string into a char * and place it in the char **.

For example char * text = "fus roh dah char **newtext = (...size allocated) So I'd want to have:

char * t1 = "fus", t2 = "roh", t3 = "dah";
newtext[0] = t1;
newtext[1] = t2;
newtext[2] = t3;

I've tried breaking the original up and making the whitespace into '\\0' but I'm still having trouble getting the char * allocated and placed into char**

Answer 1

Try this char *newtext[n]; . Here n is a constant and use this if n is known beforehand.
Otherwise char **newtext = malloc(n * sizeof *newtext); here n is a variable.

Now you can assign char* as in your example:

newtext[0] = t1;
newtext[1] = t2;
newtext[2] = t3;
...
newtext[n-1] = ..;

Hope that helps.

Answer 2

Assuming that you know the number of words , it is trivial:

char **newtext = malloc(3 * sizeof(char *));   // allocation for 3 char *
// Don't: char * pointing to non modifiable string litterals
// char * t1 = "fus", t2 = "roh", t3 = "dah";
char t1[] = "fus", t2[] = "roh", t3[] = "dah"; // create non const arrays

/* Alternatively
char text[] = "fus roh dah";    // ok non const char array
char *t1, *t2, *t3;
t1 = text;
text[3] = '\0';
t2 = text + 4;
texts[7] = '\0';
t3 = text[8];
*/
newtext[0] = t1;
newtext[1] = t2;
newtext[2] = t2;