正则表达式：我正在编写一个正则表达式以匹配子字符串并返回url部分的其余部分

Question

i have a url something like http://www.abc.def/bill/part1/part2 on which perforing regex which checks for bill and returns the rest part of the url ie bill/part1/part2

Below the code which i am trying to make work "http://www.abc.def/bill/part1/part2".match(/^bill\\:(.*)$/gm)

Answer

With validation ("http://www.abc.def/bill/part1/part2".match(/bill(.*)$/gm) || [])[0]

Answer 1

You use URL constructor and can check .pathname of the URL

 let url = new URL("http://www.abc.def/bill/part1/part2"); if (/\\/bill\\//.test(url.pathname)) console.log(url.pathname.slice(1)); 

Answer 2

Removing front carat ^ and \\: worked for you

Explanation

• bill to match string starting from bill
• (.*)$ matches rest of the input till end of string

Demo

 var output = "http://www.abc.def/bill/part1/part2".match(/bill(.*)$/gm) console.log(output); 

Answer 3

You can just match anything after (and including) bill :

 console.log( 'http//:www.abc.def/bill/part1/part2' .match(/bill(.*)/)[0] ) 

But using proper URL parsing with the URL object (see answer by guest271314 ) or a library like url-parse would likely be a better approach:

 console.log( urlParse( 'http://www.abc.def/bill/part1/part2' ).pathname.slice(1) ) 

 <script src="https://wzrd.in/standalone/url-parse@latest"></script> 

Answer 4

Your regex ^bill\\:(.*)$ does not match bill/part1/part2 because you use an anchor ^ to assert the position at the start of the string. You also specify \\: after bill , but : is not present after bill in the example.

If you want to return bill/part1/part2 , you could use bill.*$ without the capturing group (.*) .

 var match = "http://www.abc.def/bill/part1/part2".match(/bill.*$/); console.log(match[0]);