[英]Compare two rows in the same table for equality in SQL
I have the following table in my database: 我的数据库中有以下表格:
Table name: INSURANCE TABLE 表名:INSURANCE TABLE
ID | Policy
1 | 34564
2 | 67548
3 | 34564
4 | 98271
5 | 90198
6 | 98271
I am looking for a sql query that will compare the Policy column values in all 5 rows and return those rows which have a value equal to atleast one other row. 我正在寻找一个SQL查询,它将比较所有5行中的Policy列值,并返回那些值等于至少另一行的行。
For the table above I should get the following result set: 对于上表,我应该得到以下结果集:
1 | 1 | 34564 34564
3 | 3 | 34564 34564
4 | 4 | 98271 98271
6 | 6 | 98271 98271
I would appreciate responses on how to write this query. 我很感激如何编写此查询的回复。
If I understand you, you want to group by Policy, discarding unique values: 如果我了解您,您希望按策略分组,丢弃唯一值:
select * from your_table where Policy in (
select Policy from your_table group by Policy having count(*) > 1
);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.