如何使用javascript将数字转换为字符？

Question

How to convert 1234567890 = ABCDEFGHIJ , For eg. 360 to CFJ

I know how to do it for single character:

var chr = String.fromCharCode(97 + n); // where n is 0, 1, 2 ...

but not sure how can I do it for multiple/group of number at once: For eg. 230 to BCJ

Answer 1

This would work:

 function convert(num) { return num .toString() // convert number to string .split('') // convert string to array of characters .map(Number) // parse characters as numbers .map(n => (n || 10) + 64) // convert to char code, correcting for J .map(c => String.fromCharCode(c)) // convert char codes to strings .join(''); // join values together } console.log(convert(360)); console.log(convert(230));

And just for fun, here's a version using Ramda :

 const digitStrToChar = R.pipe( Number, // convert digit to number R.or(R.__, 10), // correct for J R.add(64), // add 64 R.unary(String.fromCharCode) // convert char code to letter ); const convert = R.pipe( R.toString, // convert number to string R.split(''), // split digits into array R.map(digitStrToChar), // convert digit strings to letters R.join('') // combine letters ); console.log(convert(360)); console.log(convert(230));

 <script src="//cdnjs.cloudflare.com/ajax/libs/ramda/0.25.0/ramda.min.js"></script>

Answer 2

The fromCharCode accepts a list argument as parameter.

String.fromCharCode(72, 69, 76, 76, 79); for example will print 'HELLO'.

Your example data is invalid though. The letter 'A' for example is 65. You'll need to create a comma separated argument that you feed into the function. If you don't provide it as a comma separated arg, you'll be trying to parse a single key code which will most likely fail.

Answer 3

 console.log( (1234567890 + '').replace(/\\d/g, c => 'JABCDEFGHI'[c] ) ) console.log( String.fromCharCode(...[...1234567890 + ''].map(c => (+c || 10) | 64)) )

Answer 4

You'll need to define your alphabet up front. For your snippet, you seem to want 1-9 to map to AI, and 0 to J, so:

const alphabet = "JABCDEFGHI";

Then it's just a matter of using each digit of the number as an index in that alphabet:

function numberToString(num) {
    // Split out each digit of the number:
    const digits = Math.floor(num).toString().split("").map(Number);

    // Then create a new string using the alphabet:
    return digits.reduce((str, digit) => {
        return str + alphabet[digit];
    }, "");
}

That should satisfy your constraints. Here's an example of this in action:

 const alphabet = "JABCDEFGHI"; function numberToString(num) { // Split out each digit of the number: const digits = Math.floor(num).toString().split("").map(Number); // Then create a new string using the alphabet: return digits.reduce((str, digit) => { return str + alphabet[digit]; }, ""); } console.log(numberToString(360)) // CFJ console.log(numberToString(230)) // BCJ

Answer 5

For uppercase, 97 was the wrong offset, and it didn't give you the desired result with 0 being J .

360 to CFJ

230 to BCJ

 function convert(n) { return String.fromCharCode( ...n.toString().split("").map(c => (+c||10) + 0x40) ); } console.log(convert(360)); console.log(convert(230)); function onInput(elm){ console.clear() console.log( convert(elm.value) ) }

 <input oninput="onInput(this)">

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And you can do this without the initial string conversion.

 function convert(n) { var a = Array(Math.floor(Math.log10(n))+1); var i = a.length; while (n) { a[--i] = ((n%10)||10) + 0x40; n = Math.floor(n/10); } return String.fromCharCode(...a); } console.log(convert(360)); console.log(convert(230));

Answer 6

Option 1: map it

 const from = 1234567890; const answer = from .toString() // convert to string, ignore this if it's already a string .split('') // split to array .map(x => +x + 97) // convert to char code number .map(String.fromCharCode) // convert to char code .join(''); // convert back to string console.log(answer)

Option 2: pass in multiple params

 const from = 1234567890; const fromCharCodes = from .toString() // convert to string, ignore this if it's already a string .split('') // split to array .map(x => +x + 97) // convert to char code number const answer = String.fromCharCode(...fromCharCodes); console.log(answer);