python 3.6 使用 .grid 时 Tkinter 标签属性错误

Question

I am beginning to get the hang of tkinter, but I have run into a problem. I want to create a label that displays an appropriate message according to the values of an Entry field, checked by a button. When this is used repeatedly, using just the tk.Label command will just overlay on top of the existing label, So I am trying to assign the label to a variable:

messagebox=tk.Label(root2,text="                       ",font(style,font).grid(row=1,column=0,columnspan = 50))

I want to later on use the .configure command to change this text, However I get this error:

Exception in Tkinter callback
Traceback (most recent call last):
File "C:\ProgramData\Anaconda3\lib\tkinter\__init__.py", line 1699, in __call__
return self.func(*args)
File "C:[CENSORED BY POSTER (me), It was just the file directory]", line 84, in Checkpass
messagebox = tk.Label(root2,text="                       ",font=(style,font).grid(row=1,column=0,columnspan = 50))
AttributeError: 'tuple' object has no attribute 'grid'

Can anyone please tell me what I am doing wrong and explain why it wont work. Thank you, Tava

Answer 1

Check your parentheses at font(style,font).grid . Probably should be:

messagebox=tk.Label(root2,text="                       ",font(style,font)).grid(row=1,column=0,columnspan = 50)

But I personally recommend split it into two lines for the sake of readability:

messagebox = tk.Label(root2, text="                       ", font(style, font))
messagebox.grid(row=1, column=0, columnspan = 50)