如何从laravel中的user_id获取用户名？

Question

I have 2 table 1st fund 2nd users I have registered member name in users table while in fund table user_id of registered member. I want to show users name in a table where I am able to show its user_id .

<div class="deposit-body">
    <table class="table main-table">
        <tbody>
            <tr class="head">
                <th>Name</th>
                <th>Date</th>
                <th>Currency</th>
                <th>Amount</th>
            </tr>
            @foreachFund::with('user')->where('created_at', '>', Carbon::now()->subHours(24))->orderBy('id', 'desc')->take(10)->get()
                <tr>
                    <td>{{ $fund->user_id }}</td>
                    <td>{{ $fund->updated_at}}</td>
                    <td><strong>{{$basic->currency}}</strong></td>
                    <td><strong>{{ $fund->total }}</strong></td>
                </tr>
            @endforeach
        </tbody>
    </table>
</div>

I have pasted following code to my Fund model. But it is not working.

public function user(){
    return $this->belongsTo('App\User', 'user_id'); 
}

Answer 1

Use relationship to access user object.

@foreach(Fund::with('user')->where('created_at', '>', Carbon::now()->subHours(24))->orderBy('id', 'desc')->take(10)->get() as $fund)
 <tr>
        <td>{{ $fund->user->name }}</td>
 </tr>
@endforeach

Answer 2

Looks like not all funds have user_id filled. In this case, you should use the optional() helper.

Move the logic to controller:

$funds = Fund::with('user')->where('created_at', '>', Carbon::now()->subHours(24))->orderBy('id', 'desc')->take(10)->get();
return view('your.view', compact('funds'));

Then in the view:

@foreach ($funds as $fund)
    {{ optional($fund->user)->name }}
@endforeach