[英]Change dependent objects based on a class attribute
For example, if I have two classes : 例如,如果我有两个类:
class A:
def __init__(self):
self.a = 1;
def update(self, val):
self.a = val;
class B:
def __init__(self, default = A()):
self.b = default.a;
Using them : object_a = A(); object_b = B(object_a);
使用它们: object_a = A(); object_b = B(object_a);
object_a = A(); object_b = B(object_a);
Then, I would like to update the object_a.a
attribute using object_a.update(update_val)
but also concurrently update at all other dependent objects ( object_b.b
will also be updated to update_val
). 然后,我想使用object_a.update(update_val)
更新object_a.a
属性,但同时对所有其他从属对象进行更新( object_b.b
也将更新为update_val
)。
How to do this in Python, is there a 'built-in' way? 如何在Python中执行此操作,是否有“内置”方式?
I already have some manual solutions in mind, such as: 我已经有了一些手动解决方案,例如:
class A:
def __init__(self):
self.a = 1;
self.dependent = None;
def update(self, val):
self.a = val;
if self.dependent != None:
self.dependent.b = self.a;
class B:
def __init__(self, default = A()):
default.dependent = self;
self.b = default.a;
One way to accomplish what you are asking is use a mutable object, such as a list, to store the attribute's data. 完成要求的一种方法是使用可变对象(例如列表)来存储属性的数据。 Since the objects will reference the list, changing the values of the list will be shared to both objects. 由于对象将引用列表,因此更改列表的值将共享给两个对象。
Here is a version that uses a list to store the underlying value, but maintains the attribute behavior .a
and .b
这是一个使用列表存储基础值但保留属性行为.a
和.b
class A:
def __init__(self):
self._a = [1]
def update(self, val):
self._a[0] = val
@property
def a(self):
return self._a[0]
class B:
def __init__(self, default):
self._b = default._a
@property
def b(self):
return self._b[0]
a = A()
b = B(a)
a.update(4)
b.b
# returns:
4
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