使用foreach循环以ID数组更新MySQL表

Question

I'm trying to update a MySQL table with three columns (id, franchise_id, state_id) with data from an array by using a foreach loop. The table updates but the four rows that match the franchise_id are being updated with the last item in the array (4). I can't figure out where the error is.

Data passed to the function:

$states = [1,2,3,4];
$franchise_id = 5;

The update function:

public static function update($franchise_id, $states)
{

    try
    {
        // establish db connection
        $db = static::getDB();

        $sql = "UPDATE franchise_states SET state_id = ? WHERE franchise_id = ?";
        $stmt = $db->prepare($sql);
        foreach($states as $state)
        {
            $stmt->execute([$state, $franchise_id]);
        }
        return $stmt;
    }
    catch (PDOException $e)
    {
       echo "Error updating franchise data: " . $e->getMessage();
       exit();
    }
}

I appreciate any help.

Thanks!

Answer 1

Actually it's updating for all the values in $states array but the last one stays because, well, it is the last executed one.

You try to update state_id against the same value franchise_id=5 and since all of them has the same franchise id, the last value stays.

Answer 2

Have you try to edit this line?

 foreach($states as $state) 

to

 foreach($state as $states)