创建模型管理页面而不创建表python

Question

I'm new to Django and Python and am starting to develop a CMS with this technology with Django CMS.

I need to create a model admin page to manage my lots entity, but i will not have this entity in my database. Basically i will display all entities of lots in the index list, consuming another service like a request. And this is the idea for the other CRUD's.

When create , update , delete I will consume a service to make this operations with the respective entity. For this I will override the CRUD methods of admin.ModelAdmin . Is there a way to do that?

I looked everywhere but without answers.

This is what I already have.

In my admin.py

from django.contrib import admin
from cms.extensions import PageExtensionAdmin
from .models import LoteDestaque
from .models import LoteDestaqueTest

# from myproject.admin_site import custom_admin_site

@admin.register(LoteDestaqueTest)

Here is my models.py

from .servicos.lotes import * 
from django import forms
from django.db import models
from django.utils.translation import ugettext_lazy as _
from datetime import datetime
from cms.models import CMSPlugin
from djangocms_text_ckeditor.fields import HTMLField


class LoteDestaqueTest():
    lotes = lotes.buscaLotes()
    lote_id = forms.ChoiceField(choices=(lotes))
    nome = models.CharField(max_length=150, verbose_name = _('Nome'))
    imagem = models.CharField(max_length=200, verbose_name = _('Imagem'), blank=True, null=True)
    observacoes = models.CharField(max_length=200, verbose_name = _('Observações'), blank=True, null=True)
    descricao = HTMLField(verbose_name = _('Descrição'), blank=True, null=True)
    valor =  models.DecimalField(max_digits=9, decimal_places=2, verbose_name = _('Valor'), blank=True, null=True)
    origem = models.CharField(max_length=50, verbose_name = _('Origem'), blank=True, null=True)
    tipo = models.CharField(max_length=50, verbose_name = _('Tipo'), blank=True, null=True)
    data_exposicao = models.DateTimeField(verbose_name = _('Data Exposição'), blank=True, null=True)
    ativo = models.BooleanField(default=True, verbose_name = _('Ativo'), blank=True)
    criado = models.DateTimeField(auto_now=True, editable=False, blank=True, null=True)
    atualizado = models.DateTimeField(auto_now=True, editable=False, blank=True, null=True)

    def __str__(self):
        return self.nome

    class Meta:
        verbose_name = _('Lote em Destaque Test')
        verbose_name_plural = _('Lotes em Destaque Test')

My apps.py

from django.apps import AppConfig


class LoteLeiloesConfig(AppConfig):
    name = 'leiloes_lotes_plugin'

And here is the integration in settings.py

INSTALLED_APPS = (
    'leiloes_lotes_plugin.apps.LoteLeiloesConfig',
    'djangocms_admin_style',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.admin',
    'django.contrib.sites',
    'django.contrib.sitemaps',
    'django.contrib.staticfiles',
    'django.contrib.messages',
    'cms',
    'menus',
    'sekizai',
    'treebeard',
    'djangocms_text_ckeditor',
    'filer',
    'easy_thumbnails',
    'djangocms_column',
    'djangocms_link',
    'cmsplugin_filer_file',
    'cmsplugin_filer_folder',
    'cmsplugin_filer_image',
    'cmsplugin_filer_utils',
    'djangocms_style',
    'djangocms_snippet',
    'djangocms_googlemap',
    'djangocms_video',
    'projeto'
)

Any help is usefull.

Answer 1

If what you are trying to reach is to have a ModelAdmin like class so you can get the advantages of django-admin while you handle remote resources (via API), you can try: https://github.com/mbylstra/django-wham the project last commit was in 2015, I hope this can help you in how to tackle this challenge.

Check out this question: Map Django Model to External API