[英]Decode php://input json
I have this text from file_get_contents('php://input')
: 我有来自
file_get_contents('php://input')
这段文字:
[{"email":"text@examlple.com","event":"processed","sg_event_id":"JJTr9qA","sg_message_id":"AjvX5L7IQeGOfxmJV-OCnw","smtp-id":"<AfxmJV-OCnw@ismon1.sendgrid.net>","timestamp":16813363}]
I need to get single element like email or event, but haven't been able to get json_decode
and others to work. 我需要获取单个元素,如电子邮件或事件,但无法获取
json_decode
和其他json_decode
才能正常工作。
$obj = json_decode(file_get_contents('php://input'));
How can I reference a single element in the json data? 如何引用json数据中的单个元素?
You have an array, so, you need to get the first element: 您有一个数组,因此,需要获取第一个元素:
$json = '[{"email":"text@examlple.com","event":"processed","sg_event_id":"JJTr9qA","sg_message_id":"AjvX5L7IQeGOfxmJV-OCnw","smtp-id":"<AfxmJV-OCnw@ismon1.sendgrid.net>","timestamp":16813363}]';
$obj = json_decode($json);
echo $obj[0]->email; //output text@examlple.com
Here you go, here's a fully working answer: 到这里,这是一个完全有效的答案:
<?php
$str = '[{"email":"text@examlple.com","event":"processed","sg_event_id":"JJTr9qA","sg_message_id":"AjvX5L7IQeGOfxmJV-OCnw","smtp-id":"<AfxmJV-OCnw@ismon1.sendgrid.net>","timestamp":16813363}]';
$obj = json_decode($str);
echo $obj[0]->email;
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