如果数组包含特定字符，则返回所有字符串php

Question

Let's say I have a php array like this:

$compare  = array("Testing", "Bar");
$my_array = array(
                "Foo=7654", "Bar=4.4829", "Testing=123" 
        );

So it's safe to say below:

$compare[0] = "Testing"  

So I wanna check if $my_array contains $compare[0] (in above case, yes it does) And if it contains returns that value from $my_array which is Testing=123

How's that possible?

Answer 1

You may use foreach loop:

$result = array();
foreach ($compare as $comp) {
    foreach ($my_array as $my) {
        if (strpos($my, $comp) !== false) {
            $result[] = $comp;
        }
    }
}

in array $result is result of search

or by other way:

$result = array();
foreach ($compare as $comp) {
    foreach ($my_array as $my) {
        if ($comp = explode('=', $my)[0]) {
            $result[] = $comp;
        }
    }
}

Answer 2

To use a single loop...

$compare  = array("Testing", "Bar");
$my_array = array(
    "Foo=7654", "Bar=4.4829", "Testing=123"
);
$output = [];

foreach ( $my_array as $element )   {
    if ( in_array(explode('=', $element)[0], $compare)){
        $output[] = $element;
    }
}
print_r($output);

This just checks that the first part of the value (before the =) is in the $compare array.