有条件的Django模型创建

Question

I am writing a app for django which i am planning to publish. This app requires a Bolean Setting variable CONSUMER_REGISTRATION .

Aim of getting this variable is to decide whether to define ConsumerRegistrationModel or not.

This is what I did.

from django.db import models
from django.conf import settings

if getattr(settings, 'CONSUMER_REGISTRATION', False):
    class ConsumerRegistration(models.Model):
        ...

Its working fine. The only Issue i am facing that developers will need to run makemigrations and migrate commands each time they change the variable in settings.

1- Can this work be automated ? . So if they change the variable then some code in django auto run the makemigrations and migrate commands.

2- Or is it perfectly fine to leave this work on developers ??

3- Also I want to ask that is it a good aproach to do this in django ?

Answer 1

You could simply define the model without any conditionals and tweak your app logic so that instances of ConsumerRegistration model are only interacted with (ie created, updated etc.) when the 'CONSUMER_REGISTRATION' flag is set to True .

Running migrations every single time the value of 'CONSUMER_REGISTRATION' is changed would make much more mess than leaving ConsumerRegistration table empty.

As indicated by @ dahrens , you could isolate the ConsumerRegistration model along with relevant logic in a separate app, which would only be installed as needed by developers.