Javascript：删除所有事件侦听器

Question

What's the best way to remove all event listeners? I've got something like this (using jQuery) but I'm not sure if this is the best way to go about it:

// Remove all the event listernes
$('*').off('blur click change dblclick each error focus focusin focusout keydown keypress keyup load mousedown mouseup mousemove mouseover mouseout mouseenter mouseleave popstate resize scroll select submit unload');
$(window).off('scroll');

Answer 1

$("body").find("*").off();

这将删除主体中所有元素上的所有事件侦听器

Answer 2

Does .unbind() not do the trick?

Eg:

 $("#click_for_hello").on("click",function(){ alert("hello"); }) $("#click_for_hello").unbind(); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <button id="click_for_hello">Click me</button>