如何删除指定字符之间的字符串并存储删除的字符串（Javascript）

Question

Let's say I have a string:

"but i [C#min] do [G#min] believe there's"

How to I turn that string into:

"but i  do  believe there's" (basically removing everything in-between '[' and ']')

And I would like to have [C#min] & [G#min] stored in an another array.

Answer 1

  var a = "but i [C#min] do [G#min] believe there's"; console.log(a.replace(/\\[(.[^\\[\\]]*)\\]/g, '')); // "but i do believe there's" console.log(a.match(/\\[(.[^\\[\\]]*)\\]/g)); // ["[C#min]", "[G#min]"] 

The RegExp matches for everything between [ , ] except for [ , ] themselves.

You might need to remove extra white spaces left around the replacements.

Answer 2

You may use a regular expression:

  var text = "but i [C#min] do [G#min] believe there's"; var regexp = /(\\[[^\\]]*\\])/g; var matches = text.match(regexp); text = text.replace(regexp, '').replace(/ /g, ' '); console.log(text); 

matches will contain the array ["[C#min]", "[G#min]"] .

Note: the second replace for text handles the incorrectly remaining double spaces.

Answer 3

Try this straightforward way:

  var str = "but i [C#min] do [G#min] believe there's"; var start, stop, newStr = '', removed = '', counter =1; while(str.search(/\\[.*\\]/g) > 0) { start = str.indexOf('['); stop = str.indexOf(']'); newStr += str.substring(0, start); removed += str.substring(start, stop+1); str = str.substring(stop+1, str.length); counter++; if(counter > 3) break; } newStr += str; console.log(newStr); 

Answer 4

Without Regex, simple way:

  var string = "but i [C#min] do [G#min] believe there's"; array = []; filteredString = "" for (i=0;i<string.length;i++){ if (string[i] != '[') { filteredString += string[i]; continue; } newstring = ""+string[i]; do { newstring += string[++i]; } while (string[i]!=']'); array.push(newstring); } console.log(array); console.log(filteredString); 

Answer 5

You can use a regular expression to find the bracketed strings and then strip them out with String.replace() . The stripped out portions will be in an array for whatever use you need them for.

 var input = "but i [C#min] do [G#min] believe there's"; var reg = /\\[(.*?)\\]/g; // Patthen to find var matches = input.match(reg); // Find matches and populate array with them var output = input.replace(reg, "").replace(/\\s\\s/g, " "); // Strip out the matches and fix spacing console.log(matches); // Just for testing console.log(output); // Result 

Answer 6

You could split the string by [:

function parseString(input) {
    output = {
        values: [],
        result: ""
    };
    input = input.split('[');
    for (var index = 0; index < input.length; index++) {
        var closingPosition = input[index].indexOf("]");
        if ((index > 0) && (closingPosition + 1)) {
            output.values.push('[' + input[index].substring(0, closingPosition) + ']');
            if (input[index].length > closingPosition) {
                output.result += input[index].substring(closingPosition + 1);
            }
        } else {
            output.result += input[index];
        }
    }
    return output;
}