从数组lodash中删除项目

Question

i've two array and I want to remove entries that exist in array 2 from array 1

of course I can loop and create new array but my question is if lodash have some util that can help …

var array1 = [“user1”,”user2", “user3", “user4”];


var array2 = [“user1”, “user3"];

I want that array1 will have after the remove

var array1 =[”user2", “user4”];

I saw that lodash have this but is there is better way ?

var evens = _.remove(array, function(n) {
  return n % 2 == 0;
});

Answer 1

With lodash you can use _.difference(array, [values]) Where array is the array to inspect, and [values] are the values to exclude.

Check documentation at https://lodash.com/docs/4.17.4#difference

var array1 = ['user1', 'user2', 'user3', 'user4'];
var array2 = ['user2', 'user4'];

array1 = _.difference(array1, array2); //['user1','user3'];

Answer 2

If you are looking for a vanilla JS solution, you can concat your two arrays and filter out duplicated items:

 var array1 = ['user1', 'user2', 'user3', 'user4']; var array2 = ['user1', 'user3']; array1 = [...array1, ...array2].filter((e, i, self) => self.indexOf(e) === self.lastIndexOf(e)); console.log(array1); 

If you cannot use ES6 spread operator (...) , use array.prototype.concat :

 var array1 = ['user1', 'user2', 'user3', 'user4']; var array2 = ['user1', 'user3']; array1 = array1.concat(array2).filter((e, i, self) => self.indexOf(e) === self.lastIndexOf(e)); console.log(array1);