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显示用户输入的数字中的数字总和

[英]Display the sum of digits in a number entered by the user

I need to get a number from the user and display the sum of that number's digits. 我需要从用户那里得到一个数字,并显示该数字的总和。 For example, the sum of the digits in the number 12329 is 17 . 例如,数字12329中的数字1232917

Here's what I tried to do and it is giving me the ASCII code instead: 这是我尝试做的,而是给了我ASCII码:

Console.WriteLine("please enter a number: ");
string num = Console.ReadLine();
int len = num.Length;
int[] nums = new int[len];
int sum = 0;
int count = 0;
while (count < len)
{
    nums[count] = Convert.ToInt32(num[count]);
    count++;
}
for (int i = 0; i < len; i++)
    sum += nums[i];

Console.WriteLine(sum);

This is a very common mistake. 这是一个非常常见的错误。 char is really just a number - the encoding value of the character represented by the char . char实际上只是一个数字-char表示的char的编码值。 When you do Convert.ToInt32 on it, it sees the char as a number and says "alright let's just convert this number to 32 bits and return!" 当您对它执行Convert.ToInt32时,它会将char视为一个数字,并说:“好吧,我们将这个数字转换为32位并返回!” instead of trying to parse the character. 而不是尝试解析字符。

"Wait, where have I used a char in my code?" “等等,我在代码中的哪里使用了char ?” you might ask. 你可能会问。 Well, here: 好吧,在这里:

Convert.ToInt32(num[count]) // 'num[count]' evaluates to 'char'

To fix this, you need to convert the char to a string : 要解决此问题,您需要将char转换为string

nums[count] = Convert.ToInt32(num[count].ToString());
                              ^^^^^^^^^^^^^^^^^^^^^

Now you are calling a different overload of the ToInt32 method, which actually tries to parse the string. 现在,您正在调用ToInt32方法的另一个重载,该方法实际上尝试解析该字符串。

When you access your string with a index (in your case num[count] ) you get a char type and because of that you are getting ASCII values. 当您使用索引(在您的情况下为num[count] )访问字符串时,将获得一个char类型,因此将获得ASCII值。 You can convert char to string with .ToString() in your case nums[count] = Convert.ToInt32(num[count].ToString()); 您可以在情况下使用.ToString()将char转换为字符串nums[count] = Convert.ToInt32(num[count].ToString()); .I posted here another approach to your problem: 我在这里发布了另一种解决您问题的方法:

string number = Console.ReadLine();
int sum = 0;
foreach (var item in number)
{
    sum += Convert.ToInt32(item.ToString());
}
Console.WriteLine(sum);

As you noticed the Convert.ToInt32(num[count]) will only return the Unicode code of the char you want to convert, because when you use the [] operator on a string , you will get readonly access to [the] individual characters of a string [1] . 正如您所注意到的, Convert.ToInt32(num[count])将仅返回要转换的char的Unicode代码,因为当您在string上使用[]运算符时,您将获得对[the]个单个字符的只读访问权限字符串 [1]

And so you are using Convert.ToInt32(Char) , which 因此,您正在使用Convert.ToInt32(Char) ,其中

Converts the value of the specified Unicode character to the equivalent 32-bit signed integer. 将指定的Unicode字符的值转换为等效的32位带符号整数。

One way to cast the numeric value from a char to a digit, is using Char.GetNumericValue() , which 将数字值从char转换为数字的一种方法是使用Char.GetNumericValue() ,该方法

Converts a specified numeric Unicode character to a double-precision floating-point number. 将指定的数字Unicode字符转换为双精度浮点数。


By using System.Linq; 通过using System.Linq; you can cut your code to just a few lines of code. 您可以将代码缩减为几行代码。

Console.WriteLine("please enter a number: ");
string num = Console.ReadLine(); // "12329"

int sum = (int)num.Select(n => Char.GetNumericValue(n)).Sum();

Console.WriteLine(sum); // 17 

What does this line of code? 这行代码是什么?

The num.Select(n => Char.GetNumericValue(n)) will iterate over each char in your string, like your while and converts each value to a double value and return an IEnumerable<double> . num.Select(n => Char.GetNumericValue(n))将遍历字符串中的每个char,就像您的while ,并将每个值转换为double值并返回IEnumerable<double> The Sum() itself will iterate over each value of the IEnumerable<double> and calculate the sum as a double . Sum()本身将迭代IEnumerable<double>每个值,并将总和计算为double And since you want an integer as result the (int) casts the double into an integer value. 并且由于要使用整数作为结果,因此(int)double精度转换为整数值。


Side-Note: 边注:

You could check your input, if it is really an integer. 如果确实是整数,则可以检查您的输入。 For example: 例如:

int intValue;
if(Int32.TryParse(num, out intValue))
{
     // run the linq
}
else
{
     // re-prompt, exit, ...
}

If you are using Char.GetNumericValue() on an letter it will return -1 so for example the sum of string num = "123a29"; 如果您在一个字母上使用Char.GetNumericValue() ,它将返回-1 ,例如, string num = "123a29";的总和string num = "123a29"; will be 16 . 16

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