Javascript Arrays 与包含相反

Question

What is the correct way of removing objects that have a certain field in JavaScript?

I can include fields with the following:

filteredResult = filteredResult.filter(e => e.selectedFields.includes("Red"));

But if I wanted to remove all properties that have this field what would I do? There doesn't seem to be a "Remove" from the documentation.

Answer 1

只是否定它。

filteredResult = filteredResult.filter(e => !e.selectedFields.includes("Red"))

Answer 2

过滤结果 = 过滤结果.filter((l) => (['红色', '蓝色','黄色'].every(y => !l.selectedFields.toLowerCase().includes(y.toLowerCase()))) );

Answer 3

You can negate the includes result or probably cleaner by using the indexOf property:

const arr = [1, 2, 3];

const notIncludes1 = (arr, val) => !(arr.includes(0));
const notIncludes2 = (arr, val) => arr.indexOf(val) === -1;