如果在Linux上使用此python脚本，如何获取价值？

Question

Hey I am trying something on my new raspberry pi and i had to post my question here because I am a noob. I am trying to get the temperature of my cpu with the following command :

cmd = "vcgencmd measure_temp | awk -F"=|'" '{print $2}'
Temp = subprocess.check_output(cmd, shell = True )`

When i run vcgencmd measure_temp i get temp= x'C with x = 30/30.5/40.8 etc. I want to get the numbers only so i can make an Ifelse statement like this:

   If Temp >= 40
   print ("40+")
   elif Temp >=35
   print ("35+")
   else: 
   print ("Below 35")

But I always get this syntaxerror

Answer 1

You have quoting problems in your assignment to cmd . You're using " as the delimiter around the Pythong string, and also around the argument to -F in the shell command. That's ending the Python string. Use single quotes around the shell argument.

cmd = "vcgencmd measure_temp | awk -F'=|' '{print $2}'"

Yuo're also missing colons and indentation in your if statement. And Python is case-sensitive, so If should be if .

if Temp >= 40:
    print ("40+")
elif Temp >=35:
    print ("35+")
else: 
    print ("Below 35")

Answer 2

There were a number of issues with your code, such as the usage of " inside your string definition which was closing the string when you didn't want to, as well as the lack of colons and indentation after your if / elif / else statements. (Also just a note, as mentioned in the PEP 8 style guide try not to use variable names like Temp , as it is not one of the commonly distinguished styles)

Here's my updated version of your code which should work:

cmd = "vcgencmd measure_temp | awk -F '=|' '{print $2}'"
temp = subprocess.check_output(cmd, shell = True)

if temp >= 40:
    print("40+")
elif temp >= 35:
    print("35+")
else: 
    print("Below 35")