原则在simple_array字段中找到数字

Question

I have an entity Customer with an simple_array field processNumbers . So in the DB its saved as an comma-separated list for example: 45645,78787,1111 . Now I want to find an entry with a specific number processNumber = 1111 . I want to do it with the query builder, but I only know the direction when I have an array and I search if a DB entry is in it. This direction doesn't work, it says that there is no entry, but it is:

$customer = $queryBuilder
            ->select('customer')
            ->from(Customer::class,'customer')
            ->where(":processNumber IN (customer.processNumbers)")
            ->setParameter('processNumber', $processNumber)
            ->getQuery()->getResult();

Answer 1

If you are using Mysql, you can use the Regex Expression in the DoctrineExtension

doctrine:
    orm:
        dql:
            string_functions:
                regexp: DoctrineExtensions\Query\Mysql\Regexp

Then use the regex

$qb->andWhere('REGEXP(customer.processNumbers, :regexp) = true')
          ->setParameter('regexp', '(^1111,)|(,1111,)|(,1111$)|(^1111$)')

My regex is very basic but understable (well I hope). You can see the regex matching here: https://regex101.com/r/oNqpUf/1

Answer 2

You can also do the following:

$qb->andWhere("customer.processNumbers LIKE :key1 OR customer.processNumbers LIKE :key2 OR customer.processNumbers LIKE :key3 OR customer.processNumbers LIKE :key4");
$qb->setParameter("key", "1111");
$qb->setParameter("key2", "%,1111");
$qb->setParameter("key3", "1111,%");
$qb->setParameter("key4", "%,1111,%");