[英]Combining multiple queries into one query in SQL
I have an issue in sql as I am quite new to this.我在 sql 中有一个问题,因为我对此很陌生。
I have three queries我有三个疑问
select count(*) as range1_50to60 from Customers where age between 50 and 60;
select count(*) as range2_30to40 from Customers where age between 30 and 40;
select count(*) as range3_20to30 from Customers where age between 20 and 30;
Is there any way by which we can combine these queries into one single query .有什么方法可以将这些查询合并为一个查询。
Regards问候
Sameera萨梅拉
Use case
expressions to do conditional aggregation: 用
case
表达式进行条件聚合:
select count(case when age between 50 and 60 then 1 end) as range1_50to60,
count(case when age between 30 and 40 then 1 end) as range2_30to40,
count(case when age between 20 and 30 then 1 end) as range3_20to30
from Customers
where age between 20 and 60
The WHERE
clause isn't really needed, but may speed things up! 确实不需要
WHERE
子句,但可以加快处理速度!
You can use SUM
like this: 您可以像这样使用
SUM
:
SELECT SUM(IF(age between 50 and 60,1,0)) AS range1_50to60,
SUM(IF(age between 30 and 40,1,0)) AS range1_30to40,
SUM(IF(age between 20 and 30,1,0)) AS range1_20to30
FROM Customers
You could try joining all the querys with UNION ALL, it would end like this. 您可以尝试将所有查询与UNION ALL连接起来,这样就可以结束。
select count(*) as result from Customers where age between 50 and 60
union all
select count(*) as result from Customers where age between 30 and 40;
union all
select count(*) as result from Customers where age between 20 and 30;
The results will be: 结果将是:
row[0] for range1_50to60
row[1] for range2_30to40
row[2] for range3_20to30
First we have our dummy data首先我们有我们的虚拟数据
CREATE TABLE persons(
person_id NUMBER GENERATED BY DEFAULT AS IDENTITY,
first_name VARCHAR2(50) NOT NULL,
last_name VARCHAR2(50) NOT NULL,
age NUMBER,
PRIMARY KEY(person_id)
);
insert all
into persons(person_id,first_name,last_name,age) values(1,'jose','alvarez',32)
into persons(person_id,first_name,last_name,age) values(2,'karla','romagnoli',24)
into persons(person_id,first_name,last_name,age) values(3,'daniela','alcazar',24)
into persons(person_id,first_name,last_name,age) values(4,'jaime','camilo',44)
into persons(person_id,first_name,last_name,age) values(5,'jenifer','paola',22)
into persons(person_id,first_name,last_name,age) values(6,'camila','puertas',55)
into persons(person_id,first_name,last_name,age) values(7,'raul','duelas',30)
into persons(person_id,first_name,last_name,age) values(8,'alejandra','bautizal',60)
into persons(person_id,first_name,last_name,age) values(9,'domingo','cano',16)
into persons(person_id,first_name,last_name,age) values(10,'felipe','vaca',25)
into persons(person_id,first_name,last_name,age) values(11,'estefany','santes',28)
into persons(person_id,first_name,last_name,age) values(12,'pamela','chu',55)
into persons(person_id,first_name,last_name,age) values(13,'fernanda','zarate',67)
select 1 from dual;
Since you only want one row with the data, plus the fact that those final results are not correlated to each other, we can integrate them with a cartesian product in this way:由于您只需要一行数据,加上这些最终结果彼此不相关的事实,我们可以通过以下方式将它们与笛卡尔积集成:
select
q1.total as age20_30,
q2.total as age31_40,
q3.total as age50_60
from (
select count(*) as total from persons p
where p.age between 20 and 30
) q1, (
select count(*) as total from persons p
where p.age between 31 and 40
) q2, (
select count(*) as total from persons p
where p.age between 50 and 60
) q3 ;
And we get the next result我们得到下一个结果
age20_30![]() |
age31_40![]() |
age50_60![]() |
---|---|---|
6 ![]() |
1 ![]() |
3 ![]() |
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