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在结构中初始化数组的问题

[英]Issue initializing array inside struct

I'm trying to get a structure, which contains an integer and a pointer to another structure.我正在尝试获取一个结构,其中包含一个整数和一个指向另一个结构的指针。 This second structure is just an array of 2 strings and an array of 2 numbers.第二个结构只是一个由 2 个字符串组成的数组和一个由 2 个数字组成的数组。

What am I doing wrong here?我在这里做错了什么?

struct folder {
    char **filenames_array;
    int *images_array;
};

struct display {
    int pos_y;
    struct folder current_folder;
};

struct display g_display = {
    .pos_y = 0,
    .current_folder = {
        .filenames_array = {"002.jpg", "003.jpg"},
        .images_array = {0, 0},
    }
};

I'm getting those errors:我收到这些错误:

error C2143: syntax error : missing '}' before '.'
error C2143: syntax error : missing ';' before '.'
error C2059: syntax error : '.'
error C2143: syntax error : missing ';' before '{'
error C2447: '{' : missing function header (old-style formal list?)
error C2059: syntax error : '}'
error C2143: syntax error : missing ';' before '}'
error C2059: syntax error : '}'

You can do this with compound literal syntax:您可以使用复合文字语法来做到这一点:

struct display g_display = {
    .pos_y = 0,
    .current_folder = {
        .filenames_array = (char *[]){"002.jpg", "003.jpg"},
        .images_array = (int []){0, 0},
    }
};

Alternately, if you know your arrays will always have two elements, you can keep the current initializer syntax and declare the arrays as actual arrays instead of pointers:或者,如果你知道你的数组总是有两个元素,你可以保留当前的初始化语法并将数组声明为实际数组而不是指针:

struct folder {
    char *filenames_array[2];
    int images_array[2];
};

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