[英]ImapLib get gmail id mail(python)
Sorry for my english. 对不起我的英语不好。 For example i have link like this 例如我有这样的链接
https://mail.google.com/mail/u/0/?source=sync&tf=1&view=pt&th=1614fcf57d5cb6ec1&search=all
where 1614fcf57d5cb6ec1
it uuid message. 其中1614fcf57d5cb6ec1
是uuid消息。 By this link i can view pdf mail. 通过此链接,我可以查看pdf邮件。 For work with mail i use imaplib. 对于邮件,我使用imaplib。 I try get this uuid gmail message like this: 我尝试得到这样的uuid gmail消息,如下所示:
mail.get('Message-id')
but it give me id like this: 3CB8978E-60DD-41B1-AA2E-0685219513F3@happyplugs.com
但它会给我这样的ID: 3CB8978E-60DD-41B1-AA2E-0685219513F3@happyplugs.com
My question: Hav i can get id gmail message use imaplib? 我的问题:我可以使用imaplib获得ID gmail消息吗?
UPD: UPD:
IMAP_SERVER = 'imap.gmail.com'
IMAP_PORT = '993'
IMAP_USE_SSL = True
def __init__(self):
print("MailBox __init__")
self.user = '123@gmail.com'
self.password = '123'
if IMAP_USE_SSL:
self.imap = imaplib.IMAP4_SSL(IMAP_SERVER, IMAP_PORT)
else:
self.imap = imaplib.IMAP4(IMAP_SERVER, IMAP_PORT)
def __enter__(self):
print("MailBox __enter__")
self.imap.login(self.user, self.password)
return self
def __exit__(self, exc_type, exc_val, exc_tb):
self.imap.close()
self.imap.logout()
def get_google_id():
self.imap.select('Inbox')
status, response = self.imap.search(None, 'ALL')
if status == 'OK':
items = response[0].split()
for email_id in reversed(items):
status, response = self.imap.fetch(email_id, "(RFC822)")
if status == 'OK':
email_body = response[0][1]
mail = email.message_from_bytes(email_body)
id_mess = mail.get('Message-id') //this give me not gmail mail id
imaplib
has a separate set of functions to operate on IMAP UIDs. imaplib
具有一组单独的函数,可对IMAP UID进行操作。
status, response = self.imap.uid('search', None, "ALL")
for uid in reversed(response[0].split()):
status, response = self.imap.uid('fetch, uid, '(RFC822)')
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