运行一个简单的 C++ 函数

Question

I've just started learning the basics in C++ and currently am trying to make a program that does a few basic things. The problem I have is occurring in the pasted function below.

At this point it literally does nothing when it runs. All I'm trying to do it make it so the function runs over and over again forever, until the user enters the letter 'q'.

The function must keep running even if the user enters some random string, anything, 'q' is the only keystroke that should stop the loop.

I have tried toying around with 'cin.whatever" and haven't found success. If you have an answer please provide as much explanation as possible. Thank you!

void menu()
{
    cin.clear();
    cin.ignore();
    char quit = 'w';
    while (quit != 'q') // while loop to allow the user infinite tries
    {
        cout << "Which story would you like to play? Enter the number of the story (1, 2, or 3) or type q to quit: " << endl;
        cin >> quit;

        if (quit < '1' or quit > '3') // make sure the user picks a valid choice
        {
            cout << "Valid choice not selected." << endl;
        }
        if (quit == '1')
        {
            story1(); // run story 1
        }
        if (quit == '2')
        {
            story2(); // run story 2
        }
        if (quit == '3')
        {
            story3(); // run story 3
        }
        if (quit == 'q')
        {
            cout << "good bye" << endl;
            break;
        } 
    }
}

Answer 1

Try adding single quotes around your 1,2,3 like you did with the q. The cin is expecting a char to be entered so evaluate it as such. eg: if (quit == '1')