请求超时-套接字Java

Question

Having some problems with the following code: 以下代码存在一些问题：

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.Socket;

class Main {
    public static void main(String args[]) {
        try {
            Socket s = new Socket("ark.intel.com", 80);

            PrintWriter out = new PrintWriter(s.getOutputStream());
            out.write("GET / HTTP/1.1\r\n"
                + "Host: ark.intel.com\r\n"
                + "Connection: keep-alive\r\n"
                + "User-Agent: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36\r\n"
                + "Accept: text/html"
                + "\r\n");
            out.flush();

            BufferedReader read = new BufferedReader(new InputStreamReader(s.getInputStream()));
            String line;
            String data = "";

            while ((line = read.readLine()) != null) {
                data += line;
                System.out.println(line);
            } read.close();
        } catch (Exception error) {}
    }
}

i keep getting 我不断

HTTP/1.0 408 Request Time-out Server: AkamaiGHost Mime-Version: 1.0 Date: Tue, 06 Feb 2018 11:43:41 GMT Content-Type: text/html Content-Length: 218 Expires: Tue, 06 Feb 2018 11:43:41 GMT HTTP / 1.0 408请求超时服务器：AkamaiGHost Mime版本：1.0日期：2018年2月6日星期二11:43:41 GMT内容类型：text / html内容长度：218过期：2018年2月6日星期二11：格林尼治标准时间43:41

<HTML><HEAD>
<TITLE>Request Timeout</TITLE>
</HEAD><BODY>
<H1>Request Timeout</H1>
The server timed out while waiting for the browser's request.<P>
Reference&#32;&#35;2&#46;403b3717&#46;1517917421&#46;0
</BODY></HTML>

any idea on how to fix this? 关于如何解决这个问题的任何想法？

Edit: The host ark.intel.com is using HTTPS, i need to find a way to send the requests over HTTPS rather then HTTP. 编辑：主机ark.intel.com使用HTTPS，我需要找到一种通过HTTPS而非HTTP发送请求的方法。

Answer 1

Host ark.intel.com is using https so you should use port 443. 主机ark.intel.com使用https，因此您应该使用端口443。

Socket s = new Socket("ark.intel.com",443);

Then you will get another error, that will not be visible, because you are not handling exception 然后，您将收到另一个错误，该错误将不可见，因为您没有处理异常

} catch (Exception error) {}

Here is example how to handle secure connections with use of SSL Socket: https://docs.oracle.com/javase/8/docs/technotes/guides/security/jsse/samples/sockets/client/SSLSocketClient.java What you need to do is to change request with your parameters in this line out.println("GET / HTTP/1.0"); 以下是使用SSL套接字处理安全连接的示例： https : //docs.oracle.com/javase/8/docs/technotes/guides/security/jsse/samples/sockets/client/SSLSocketClient.java要做的就是用这一行的参数更改请求out.println（“ GET / HTTP / 1.0”）;

Answer 2

There is a missing \\r\\n: 缺少\\ r \\ n：

        + "Accept: text/html\r\n"

UPDATE 更新

As we have seen, this will allow you to do the request, but you will get a redirect, forcing you to use HTTPS. 如我们所见，这将允许您执行请求，但是您将获得重定向，从而迫使您使用HTTPS。

Try using an HttpURLConnection instead of plain sockets: 尝试使用HttpURLConnection而不是普通套接字：

    try {
        URL url = new URL("https://ark.intel.com/");
        HttpURLConnection cnt = (HttpURLConnection) url.openConnection();
        cnt.setRequestProperty("Host", "ark.intel.com");
        cnt.setRequestProperty("Connection", "keep-alive");
        cnt.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.132 Safari/537.36");
        cnt.setRequestProperty("Accept", "text/html");

        int stat = cnt.getResponseCode();
        if (stat != 200) {
            throw new IOException("HTTP error " + stat);
        }
        BufferedReader read = new BufferedReader(new InputStreamReader(cnt.getInputStream()));
        String line;
        String data = "";

        while ((line = read.readLine()) != null) {
            data += line;
            System.out.println(line);
        } read.close();
    } catch (Exception error) {
        error.printStackTrace();
    }

请求超时-套接字Java

问题描述

2 个解决方案

解决方案1
1 2018-02-06 11:58:33

解决方案2
1 已采纳 2018-02-06 12:05:24

请求超时-套接字Java

问题描述

2 个解决方案

解决方案1 1 2018-02-06 11:58:33

解决方案2 1 已采纳 2018-02-06 12:05:24

解决方案1
1 2018-02-06 11:58:33

解决方案2
1 已采纳 2018-02-06 12:05:24