[英]Oracle Update with Regular Expression
I have some values in a column like:我在列中有一些值,例如:
"This is test $ABC variables." “这是测试 $ABC 变量。”
I want to update all the variable definition to below one:我想将所有变量定义更新为以下一个:
"This is test $ABC$ variables." “这是测试 $ABC$ 变量。”
How can I write this update statement?我该如何写这个更新声明? Somehow, I couldn't manage.
不知何故,我无法应付。
Do you just want replace()
?你只想要
replace()
吗?
update t
set col = replace(col, '$ABC', '$ABC$')
where col like '%$ABC%';
Unfortunately, I'm not good at regular expressions so this poor attempt of mine could probably be replaced by something smarter.不幸的是,我不擅长正则表达式,所以我这个糟糕的尝试可能会被更聪明的东西所取代。 Looking forward to see it!
期待看到它!
SQL> with test as
2 (select 'This is test $ABC variables' col from dual union
3 select 'Stackoverflow says $DEF is so cool' from dual
4 )
5 select
6 col,
7 regexp_replace(col, '\$\w+', regexp_substr(col, '\$\w+') || '$') result
8 from test;
COL RESULT
---------------------------------- ----------------------------------------
Stackoverflow says $DEF is so cool Stackoverflow says $DEF$ is so cool
This is test $ABC variables This is test $ABC$ variables
SQL>
You may use this REGEXP
query.您可以使用此
REGEXP
查询。 The parentheses in '\\$(\\w+)'
capture the word following $
in \\1
'\\$(\\w+)'
的括号捕获\\1
$
后面的单词
SELECT REGEXP_REPLACE (
'This is test $ABC variables.This is a second variable $variable2.I have 100$',
'\$(\w+)',
'$\1$')
FROM DUAL;
O/p: O/P:
This is test $ABC$ variables.This is a second variable $variable2$.I have 100$
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.