Python Pandas：为源列的每个不同值创建一个新列（使用布尔输出作为列值）

Question

I am trying to split a source column of a dataframe in several columns based on its content, and then fill this newly generated columns with a boolean 1 or 0 in the following way:

Original dataframe:

ID   source_column
A    value 1
B    NaN
C    value 2
D    value 3
E    value 2

Generating the following output:

ID   source_column    value 1    value 2    value 3
A    value 1          1          0          0
B    NaN              0          0          0
C    value 2          0          1          0
D    value 3          0          0          1
E    value 2          0          1          0

I thought about manually create each different column, and then with a function for each column and .apply, filling the newly column with a 1 or a 0, but this is highly ineffective.

Is there a quick and efficient way for this?

Answer 1

You can try:

df = pd.get_dummies(df, columns=['source_column'])

or if you prefer sklearn

from sklearn.preprocessing import OneHotEncoder
enc = OneHotEncoder()
matrix=enc.fit_transform(df['source_column'])

Answer 2

You can use the pandas function get_dummies, and add the result to df as shown below

In [1]: col_names = df['source_column'].dropna().unique().tolist()

In [2]: df[col_names] = pd.get_dummies(df['source_column'])

In [3]: df
Out[3]: 
  ID source_column  value 1  value 2  value 3
0  A       value 1        1        0        0
1  B          NaN         0        0        0
2  C       value 2        0        1        0
3  D       value 3        0        0        1
4  E       value 2        0        1        0

Answer 3

So there is this possibility (a little bit hacky).

Reading the DataFrame from your example data:

In [4]: df = pd.read_clipboard().drop("ID", axis=1)

In [5]: df
Out[5]:
   source_column
A            1.0
B            NaN
C            2.0
D            3.0
E            2.0

After that, adding a new column with df['foo'] = 1 .

Then work with unstacking :

In [22]: df.reset_index().set_index(['index', 'source_column']).unstack().fillna(0).rename_axis([None]).astype(int)
Out[22]:
              foo
source_column NaN 1.0 2.0 3.0
A               0   1   0   0
B               1   0   0   0
C               0   0   1   0
D               0   0   0   1
E               0   0   1   0

You then of course have to rename your columns and drop the Nan col, but that should fulfill your needs in a first run.

EDIT:

Other approach to suppress the nan column, you can use groupby+value_counts (kind of hacky too):

In [30]: df.reset_index().groupby("index").source_column.value_counts().unstack().fillna(0).astype(int).rename_axis([None])
Out[30]:
source_column  1.0  2.0  3.0
A                1    0    0
C                0    1    0
D                0    0    1
E                0    1    0

This is the same idea (unstacking) but suppresses the nan values to be considered by default. You of course have to merge it on the original dataframe to keep the rows with the nan values if you want that. So at all, both approaches work fine, you can choose the one which fulfills your needs best.

Answer 4

pd.concat([df,pd.crosstab(df.index,df.source_column)],1).fillna(0)

Out[1028]: 
  ID source_column  value1  value2  value3
0  A        value1     1.0     0.0     0.0
1  B             0     0.0     0.0     0.0
2  C        value2     0.0     1.0     0.0
3  D        value3     0.0     0.0     1.0
4  E        value2     0.0     1.0     0.0