Laravel 如何在分页上的模型上显示 $hidden 属性

Question

I'm using Laravel 5.5. I read about this and know this function and it works makeVisible

$hidden = ['password', 'remember_token', 'email'];

I can display email using

$profile = auth()->user()->find($request->user()->id);
$profile->makeVisible(['email']);

On the frontend email is displayed. But it not works on many results like

 // Get all users
 $users = User::with('role', 'level')->makeVisible(['email'])->paginate(10); // Doesn't work

Also try this method from Laracasts toJson it works but I can't do it using paginate. Can you provide other methods or how to solve this? My aim is to display email column that is hidden. Thanks.

Answer 1

I solve this using this method.

Users.php on model

public function toArray()
{
    // Only hide email if `guest` or not an `admin`
    if (auth()->check() && auth()->user()->isAdmin()) {
        $this->setAttributeVisibility();
    }

    return parent::toArray();
}

public function setAttributeVisibility()
{
    $this->makeVisible(array_merge($this->fillable, $this->appends, ['enter_relationship_or_other_needed_data']));
}

and on controller just a simple

return User::with('role', 'level')->paginate(10);

I've read where pagination comes from toArray before creating pagination. Thanks for all your help. Also helps

Answer 2

You can use this:

    $paginator = User::with('role', 'level')->paginate($pageSize);
    $data = $pagination->getCollection();
    $data->each(function ($item) {
        $item->setHidden([])->setVisible(['email']);
    });
    $paginator->setCollection($data);
    return $paginator;

Answer 3

You can try to use this approach. Using API Resources .

API Resources lets you format the data the way you want. You can create multiple Resource object to format in different ways your collections.

Set visible your parameter (in this case email ) and when you need to return that item you can use a different Resource object that returns that elemement.

So when no need for email:

$users = User::with('role', 'level')->paginate(10);
return UserWithoutEmail::collection($users);

when email is needed:

$users = User::with('role', 'level')->paginate(10);
return UserWithEmail::collection($users);

Answer 4

Another, possible easier solution depending on your requirements, is to call makeVisible on the collection:

// Get all users
$users = User::with('role', 'level')->paginate(10)->makeVisible(['email']);

You can also use this with find or get :

$profile = auth()->user()->find($request->user()->id)->makeVisible(['email']);