用c从字符串中删除一些空格

Question

First my code printed yksi itsekseen lol and now it prints yksiitsekseenlol and I am trying to print yksi itsekseen lol . In the first one there are two and second there's none and I'm trying to have there only one space between the words.

My code:

#include <stdio.h>
#include <string.h>

void antikorso(char *dest, const char *src) {
    const char *p = src;
    int i;

    for (i = 0; *p != '\0'; i++, p++)
    {
        if (*p == 'x') {
            dest[i++] = 'k';
            dest[i] = 's';
        }
        else if (*p == 'z') {
            dest[i++] = 't';
            dest[i] = 's';
        }
        else
        {
            dest[i] = *p;
        }
    }
    dest[i] = '\0';
    char *original = dest;
    char c[10] = "hello";
    while (dest = strstr(dest, c)) {
        memmove(dest, dest + strlen(c), 1 + strlen(dest + strlen(c)));
    }

    char *nat = original;
    char b[20] = "asd";
    while (dest = strstr(original, b)) {
        memmove(dest, dest + strlen(b), 1 + strlen(dest + strlen(b)));
    }
    printf("\n%s", nat);

    char *vit = nat;
    char d[10] = "  ";
    while (dest = strstr(nat, d)) {
        memmove(dest, dest + strlen(d), 1 + strlen(dest + strlen(d)));
    }
    printf("\n%s", vit);
    return vit;
    }



int main(void)
    {

    const char *lol = "hello yxi asd izexeen hello lol";
    char asd[10000];
    antikorso(asd, lol);

    }

Answer 1

Ok, so you almost have it I think, change

memmove(dest, dest + strlen(c), 1 + strlen(dest + strlen(c)));

to

memmove(dest, dest + strlen(c) - 1, 1 + strlen(dest + strlen(c)));

I think that will do it. The code was previously skipping two spaces, so if you back it up one spot, it should include one space in the copy.

That should work for collapsing two spaces down to one space anyway. You should test what happens if you end up with three spaces in a row.