[英]Django Rest Framework: Serializing a model and grouping by a foreign key for other data
I have the following three models:我有以下三个模型:
class Package(models.Model):
name = models.CharField()
class Part(models.Model):
name = models.CharField()
sku = models.IntegerField()
class Member(models.Model):
name = models.CharField()
class MemberPurchase(models.Model):
member = models.ForeignKey(Member)
package = model.ForeignKey(Package)
part = models.ForeignKey(Part)
purchase_date = models.DateField()
I want to serialize MemberPurchase model for an API so that I can have all the information I need as below:我想序列化 API 的 MemberPurchase 模型,以便我可以获得所需的所有信息,如下所示:
{
"name": "John Doe",
"id": 123,
"purchases": [
{
"name": "Package Silver",
"parts": [
{
"name": "Part Silver 1",
"sku": "12345",
},
{
"name": "Part Silver 2",
"sku": "145678",
}
]
},
{
"name": "Package Gold",
"parts": [
{
"name": "Part Gold 1",
"sku": "1010101",
}
]
}
]
}
I am not exactly sure how to build the serializer to give me the result above.我不太确定如何构建序列化程序来给我上面的结果。 I can write a serializer that will serialize a queryset from
MemberPurchase
but that will have a lot of repeated data.我可以编写一个序列化程序来序列化来自
MemberPurchase
但这将有很多重复的数据。
I am guessing this needs multiple serializers:我猜这需要多个序列化程序:
class MemberSerializer(serializers.ModelSerilaizer):
purchases = MemberPurchaseSerializer(source='memberpurchase_set', many=True)
class Meta:
model = Member
fields = ['name', 'id']
class MemberPurchaseSerializer(serializers.Serializer):
name = serializers.SerializerMethodField('get_package_name')
parts = PackagePartSerializer(many=True)
def get_pacakage_name(self, instance):
return instance.package.name
class PackagePartSerializer(serializers.Serializer):
name = serializers.SerializerMethodField('get_part_name')
sku = serializers.SerializerMethodField('get_part_sku')
def get_part_name(self, instance):
return instance.part.name
def get_part_sku(self, instance):
return instance.part.sku
I don't think the above will produce what I need.我认为以上不会产生我需要的东西。 Is there a better way to do this and get the results above?
有没有更好的方法来做到这一点并获得上述结果?
Edit: So I decided to take this path but not sure if this is the most efficient implementation:编辑:所以我决定走这条路,但不确定这是否是最有效的实现:
class PackagePartSerializer(serializers.Serializer):
name = serializers.SerializerMethodField('get_part_name')
sku = serializers.SerializerMethodField('get_part_sku')
def get_part_name(self, instance):
return instance.part.name
def get_part_sku(self, instance):
return instance.part.sku
class MemberSerializer(serializers.ModelSerilaizer):
purchases = serializers.SerializerMethodField('get_member_purchases')
def get_member_purchases(self, instance):
mem_purchases = instance.memberpurchase_set.all()
purchases = []
for pur in mem_purchases:
purchases.append({
"name": pur.package.name,
"id": pur.package.id,
"parts": PackagePartSerializer(instance.memberpurchase_set.all(), many=True).data
})
return purchases
class Meta:
model = Member
fields = ['name', 'id', 'purchases']
I am providing the solution I got to as an answer.我正在提供我得到的解决方案作为答案。
class PackagePartSerializer(serializers.Serializer):
name = serializers.SerializerMethodField('get_part_name')
sku = serializers.SerializerMethodField('get_part_sku')
def get_part_name(self, instance):
return instance.part.name
def get_part_sku(self, instance):
return instance.part.sku
class MemberSerializer(serializers.ModelSerilaizer):
purchases = serializers.SerializerMethodField('get_member_purchases')
def get_member_purchases(self, instance):
mem_purchases = instance.memberpurchase_set.all()
purchases = []
for pur in mem_purchases:
purchases.append({
"name": pur.package.name,
"id": pur.package.id,
"parts": PackagePartSerializer(instance.memberpurchase_set.all(), many=True).data
})
return purchases
class Meta:
model = Member
fields = ['name', 'id', 'purchases']
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